1856 United States presidential election in Texas

Main article: 1856 United States presidential election

1856 United States presidential election in Texas

November 4, 1856

Nominee James Buchanan Millard Fillmore Party Democratic Know Nothing Home state Pennsylvania New York Running mate John C. Breckinridge Andrew J. Donelson Electoral vote 4 0 Popular vote 31,169 15,639 Percentage 66.59% 33.41%

County Results Buchanan   50-60%   60-70%   70-80%   80-90%   90-100% Fillmore   50-60%

President before election Franklin Pierce Democratic Elected President James Buchanan Democratic

The 1856 United States presidential election in Texas was held on Tuesday November 4, as part of the 1856 United States presidential election. State voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.

Texas voted for the Democratic nominee James Buchanan, who received 67% of the vote. Texas was Buchanan's second-strongest state.

Republican Party nominee John C. Frémont was not on the ballot. Texas would never be won by a Republican candidate until Herbert Hoover narrowly won the state in 1928.^[1]

Results

1856 United States presidential election in Texas[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	James Buchanan	31,169	66.589%	4
	Know-Nothing	Millard Fillmore	15,639	33.411%	0
Total			46,808	100.0%	4

See also

• United States presidential elections in Texas

References

1. "Republican Party". Britannica Kids. Retrieved 2023-12-22.
2. "David Leip's Atlas of U.S. Presidential Elections".