1856 United States presidential election in New Hampshire

Main article: 1856 United States presidential election

1856 United States presidential election in New Hampshire

November 4, 1856

Nominee John C. Frémont James Buchanan Party Republican Democratic Home state California Pennsylvania Running mate William L. Dayton John C. Breckinridge Electoral vote 5 0 Popular vote 37,473 31,891 Percentage 53.71% 45.71%

County Results Frémont   50-60%   60-70% Buchanan   50-60%

President before election Franklin Pierce Democratic Elected President James Buchanan Democratic

The 1856 United States presidential election in the New Hampshire took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire was won by former California Senator John C. Frémont, who won the state by a narrow vote margin of less than 6,000 votes. He then lost nationally to former United States Minister to the United Kingdom James Buchanan.

This was a realigning election for New Hampshire, which had been a Democrat-dominated state since the Jackson Administration. The new Republican Party quickly established itself and the Granite State would not be carried by a Democrat presidential candidate again until 1912.

Results

1856 United States presidential election in New Hampshire[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	John C. Frémont of California	William L. Dayton of New Jersey	37,473	53.71%	5	100.00%
	Democratic	James Buchanan of Pennsylvania	John C. Breckinridge of Kentucky	31,891	45.71%	0	0.00%
	Know Nothing	Millard Fillmore of New York	Andrew Jackson Donelson of Tennessee	410	0.59%	0	0.00%
Total				69,774	100.00%	5	100.00%

See also

• United States presidential elections in New Hampshire

References

1. "1856 Presidential General Election Results - New Hampshire".