1890 New Hampshire gubernatorial election

For related races, see 1890 United States gubernatorial elections.

1890 New Hampshire gubernatorial election

November 4, 1890

Nominee Hiram A. Tuttle Charles H. Amsden Party Republican Democratic Popular vote 42,479 42,386 Percentage 49.26% 49.15%

County results Tuttle:      40–50%      50–60% Amsden:      40–50%      50–60%

Governor before election David H. Goodell Republican Elected Governor Hiram A. Tuttle Republican

The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.

General election

Candidates

Major party candidates

• Hiram A. Tuttle, Republican
• Charles H. Amsden, Democratic

Other candidates

• Josiah M. Fletcher, Prohibition

Results

1890 New Hampshire gubernatorial election^[1]

Party		Candidate	Votes	%	±%
	Republican	Hiram A. Tuttle	42,479	49.26%
	Democratic	Charles H. Amsden	42,386	49.15%
	Prohibition	Josiah M. Fletcher	1,343	1.56%
Majority			93
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 16, 2020.