In mathematics, a function f is logarithmically convex or superconvex[1] if log ∘ f {\displaystyle {\log }\circ f} , the composition of the logarithm with f, is itself a convex function.
Let X be a convex subset of a real vector space, and let f : X → R be a function taking non-negative values. Then f is:
Here we interpret log 0 {\displaystyle \log 0} as − ∞ {\displaystyle -\infty } .
Explicitly, f is logarithmically convex if and only if, for all x1, x2 ∈ X and all t ∈ [0, 1], the two following equivalent conditions hold:
Similarly, f is strictly logarithmically convex if and only if, in the above two expressions, strict inequality holds for all t ∈ (0, 1).
The above definition permits f to be zero, but if f is logarithmically convex and vanishes anywhere in X, then it vanishes everywhere in the interior of X.
If f is a differentiable function defined on an interval I ⊆ R, then f is logarithmically convex if and only if the following condition holds for all x and y in I:
This is equivalent to the condition that, whenever x and y are in I and x > y,
Moreover, f is strictly logarithmically convex if and only if these inequalities are always strict.
If f is twice differentiable, then it is logarithmically convex if and only if, for all x in I,
If the inequality is always strict, then f is strictly logarithmically convex. However, the converse is false: It is possible that f is strictly logarithmically convex and that, for some x, we have f ″ ( x ) f ( x ) = f ′ ( x ) 2 {\displaystyle f''(x)f(x)=f'(x)^{2}} . For example, if f ( x ) = exp ( x 4 ) {\displaystyle f(x)=\exp(x^{4})} , then f is strictly logarithmically convex, but f ″ ( 0 ) f ( 0 ) = 0 = f ′ ( 0 ) 2 {\displaystyle f''(0)f(0)=0=f'(0)^{2}} .
Furthermore, f : I → ( 0 , ∞ ) {\displaystyle f\colon I\to (0,\infty )} is logarithmically convex if and only if e α x f ( x ) {\displaystyle e^{\alpha x}f(x)} is convex for all α ∈ R {\displaystyle \alpha \in \mathbb {R} } .[2][3]
If f 1 , … , f n {\displaystyle f_{1},\ldots ,f_{n}} are logarithmically convex, and if w 1 , … , w n {\displaystyle w_{1},\ldots ,w_{n}} are non-negative real numbers, then f 1 w 1 ⋯ f n w n {\displaystyle f_{1}^{w_{1}}\cdots f_{n}^{w_{n}}} is logarithmically convex.
If { f i } i ∈ I {\displaystyle \{f_{i}\}_{i\in I}} is any family of logarithmically convex functions, then g = sup i ∈ I f i {\displaystyle g=\sup _{i\in I}f_{i}} is logarithmically convex.
If f : X → I ⊆ R {\displaystyle f\colon X\to I\subseteq \mathbf {R} } is convex and g : I → R ≥ 0 {\displaystyle g\colon I\to \mathbf {R} _{\geq 0}} is logarithmically convex and non-decreasing, then g ∘ f {\displaystyle g\circ f} is logarithmically convex.
A logarithmically convex function f is a convex function since it is the composite of the increasing convex function exp {\displaystyle \exp } and the function log ∘ f {\displaystyle \log \circ f} , which is by definition convex. However, being logarithmically convex is a strictly stronger property than being convex. For example, the squaring function f ( x ) = x 2 {\displaystyle f(x)=x^{2}} is convex, but its logarithm log f ( x ) = 2 log | x | {\displaystyle \log f(x)=2\log |x|} is not. Therefore the squaring function is not logarithmically convex.
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