Lincoln
Douglas
James Buchanan Democratic
Abraham Lincoln Republican
The 1860 United States presidential election in Vermont took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for president and vice president.
Vermont was won by Republican candidate Abraham Lincoln and his running mate Hannibal Hamlin They defeated Democratic candidate Stephen A. Douglas and his running mate Herschel V. Johnson. Lincoln won the state by a landslide margin of 56.45%.
With 75.86% of the popular vote, Vermont would be Lincoln's strongest victory in terms of percentage in the popular vote.[1]
John S. Robinson, Henry Keyes, Jasper Rand, and E.M. Brown were the at-large delegates to the Democratic National Convention in Charleston, South Carolina, with Henry Clark, T.C. Beattie, W.W. White, and E. Plympton as their substitutes. The 1st district was represented by Charles G. Eastman and Pitt W. Hyde (J.A.S. White and John Jackson as substitutes), the 2nd district by Henry E. Stoughton and E.B. Chase (C.N. Davenport and Stephen Thomas as substitutes), and the 3rd district by H.B. Smith and Lucius Robinson (Bradley Smalley and Emory Stewart as substitutes).[2]
Republican
Democratic
Southern Democratic
Constitutional Union
This Vermont elections-related article is a stub. You can help Wikipedia by expanding it.