1844 United States presidential election in Indiana

Main article: 1844 United States presidential election

1844 United States presidential election in Indiana

November 1 - December 4, 1844

Nominee James K. Polk Henry Clay Party Democratic Whig Home state Tennessee Kentucky Running mate George M. Dallas Theodore Frelinghuysen Electoral vote 12 0 Popular vote 70,181 67,867 Percentage 50.07% 48.42%

County Results Polk   40-50%   50-60%   60-70%   70-80%   80-90% Clay   40-50%   50-60%   60-70%

President before election John Tyler Independent Elected President James K. Polk Democratic

The 1844 United States presidential election in Indiana took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Indiana by a narrow margin of 1.65%.

Results

1844 United States presidential election in Indiana[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	James K. Polk of Tennessee	George M. Dallas of Pennsylvania	70,181	50.07%	12	100.00%
	Whig	Henry Clay of Kentucky	Theodore Frelinghuysen of New York	67,867	48.42%	0	0.00%
	Liberty	James G. Birney of Michigan	Thomas Morris of Ohio	2,106	1.50%	0	0.00%
Total				140,154	100.00%	12	100.00%

See also

• United States presidential elections in Indiana

References

1. "1844 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved December 23, 2013.