1832 United States presidential election in Indiana

Main article: 1832 United States presidential election

1832 United States presidential election in Indiana

November 2 – December 5, 1832

Nominee Andrew Jackson Henry Clay Party Democratic National Republican Home state Tennessee Kentucky Running mate Martin Van Buren John Sergeant Electoral vote 9 0 Popular vote 31,551 15,472 Percentage 67.10% 32.90%

County Results Jackson   50-60%   60-70%   70-80%   80-90% Clay   50-60%   60-70% Tie   50% Unknown/No vote

The 1832 United States presidential election in Indiana took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Indiana by a margin of 34.20%.

As of 2020, this remains the strongest performance by a Democrat in Indiana.^[1]

Results

1832 United States presidential election in Indiana[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Andrew Jackson (incumbent)	31,551	67.10%	9
	National Republican	Henry Clay	15,472	32.90%	0
Totals			47,023	100.0%	9

See also

• United States presidential elections in Indiana

References

1. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved January 10, 2023.
2. "1832 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved April 12, 2013.