In mathematics, in the branch of complex analysis, a holomorphic function on an open subset of the complex plane is called univalent if it is injective.[1][2]
The function f : z ↦ 2 z + z 2 {\displaystyle f\colon z\mapsto 2z+z^{2}} is univalent in the open unit disc, as f ( z ) = f ( w ) {\displaystyle f(z)=f(w)} implies that f ( z ) − f ( w ) = ( z − w ) ( z + w + 2 ) = 0 {\displaystyle f(z)-f(w)=(z-w)(z+w+2)=0} . As the second factor is non-zero in the open unit disc, z = w {\displaystyle z=w} so f {\displaystyle f} is injective.
One can prove that if G {\displaystyle G} and Ω {\displaystyle \Omega } are two open connected sets in the complex plane, and
is a univalent function such that f ( G ) = Ω {\displaystyle f(G)=\Omega } (that is, f {\displaystyle f} is surjective), then the derivative of f {\displaystyle f} is never zero, f {\displaystyle f} is invertible, and its inverse f − 1 {\displaystyle f^{-1}} is also holomorphic. More, one has by the chain rule
for all z {\displaystyle z} in G . {\displaystyle G.}
For real analytic functions, unlike for complex analytic (that is, holomorphic) functions, these statements fail to hold. For example, consider the function
given by f ( x ) = x 3 {\displaystyle f(x)=x^{3}} . This function is clearly injective, but its derivative is 0 at x = 0 {\displaystyle x=0} , and its inverse is not analytic, or even differentiable, on the whole interval ( − 1 , 1 ) {\displaystyle (-1,1)} . Consequently, if we enlarge the domain to an open subset G {\displaystyle G} of the complex plane, it must fail to be injective; and this is the case, since (for example) f ( ε ω ) = f ( ε ) {\displaystyle f(\varepsilon \omega )=f(\varepsilon )} (where ω {\displaystyle \omega } is a primitive cube root of unity and ε {\displaystyle \varepsilon } is a positive real number smaller than the radius of G {\displaystyle G} as a neighbourhood of 0 {\displaystyle 0} ).
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