Tin(IV) iodide, also known as stannic iodide, is the chemical compound with the formula SnI4. This tetrahedral molecule crystallizes as a bright orange solid that dissolves readily in nonpolar solvents such as benzene.[1]
Preparation
The compound is usually prepared by the reaction of iodine and tin:[2]
Sn + 2I2 → SnI4
Chemical properties
The compound hydrolyses in water.[3] In aqueous hydroiodic acid, it reacts to form a rare example of a hexaiodometallate:[2]
Tin(IV) iodide is an orange solid under standard conditions.[3] It has a cubic crystal structure with the space groupPa3 (space group no. 205), the lattice parameter a = 1226 pm and eight formula units per unit cell.[4] This corresponds approximately to a cubic close packing of iodine atoms in which 1/8 of all tetrahedral gaps are occupied by tin atoms. This leads to discrete tetrahedral SnI4 molecules.[5]
^Wiberg, Egon; Wiberg, Nils (2007). Holleman, Arnold F.; Fischer, Gerd (eds.). Lehrbuch der anorganischen Chemie (102., stark umgearbeitete und verbesserte Auflage ed.). Berlin New York: Walter de Gruyter. ISBN978-3-11-017770-1.