In the science of fluid flow, Stokes' paradox is the phenomenon that there can be no creeping flow of a fluid around a disk in two dimensions; or, equivalently, the fact there is no non-trivial steady-state solution for the Stokes equations around an infinitely long cylinder. This is opposed to the 3-dimensional case, where Stokes' method provides a solution to the problem of flow around a sphere.[1][2]
Using the polar form of results in .
After deriving the series form of u, substituting this into it along with , and changing some indices, the second boundary condition translates to
Since the complex trigonometric functions compose a linearly independent set, it follows that all coefficients in the series are zero.
Examining these conditions for every after taking into account the condition at infinity shows that and are necessarily of the form
where is an imaginary number (opposite to its own complex conjugate), and and are complex numbers. Substituting this into gives the result that globally, compelling both and to be zero. Therefore, there can be no motion – the only solution is that the cylinder is at rest relative to all points of the fluid.
Resolution
The paradox is caused by the limited validity of Stokes' approximation, as explained in Oseen's criticism: the validity of Stokes' equations relies on Reynolds number being small, and this condition cannot hold for arbitrarily large distances .[7][2]
On the contrary to Stokes' paradox, there exists the unsteady-state solution of the same problem which models a fluid flow moving around a circular cylinder with Reynolds number being small. This solution can be given by explicit formula in terms of vorticity of the flow's vector field.
Formula of the Stokes Flow around a circular cylinder
The vorticity of Stokes' flow is given by the following relation:[10]
Here - are the Fourier coefficients of the vorticity's expansion by polar angle which are defined on , - radius of the cylinder, , are the direct and inverse special Weber's transforms,[11] and initial function for vorticity satisfies no-slip boundary condition.
Special Weber's transform has a non-trivial kernel, but from the no-slip condition follows orthogonality of the vorticity flow to the kernel.[10]
Derivation
Special Weber's transform
Special Weber's transform[11] is an important tool in solving problems of the hydrodynamics. It is defined for as
where , are the Bessel functions of the first and second kind[12] respectively. For it has a non-trivial kernel[13][10] which consists of the functions .
The inverse transform is given by the formula
Due to non-triviality of the kernel, the inversion identity
is valid if . Also it is valid in the case of but only for functions, which are orthogonal to the kernel of in with infinitesimal element :
No-slip condition and Biot–Savart law
In exterior of the disc of radius the Biot-Savart law
restores the velocity field which is induced by the vorticity with zero-circularity and given constant velocity at infinity.
No-slip condition for
leads to the relations for :
where
is the Kronecker delta, , are the cartesian coordinates of .
In particular, from the no-slip condition follows orthogonality the vorticity to the kernel of the Weber's transform :
Vorticity flow and its boundary condition
Vorticity for Stokes flow satisfies to the vorticity equation or in terms of the Fourier coefficients in the expansion by polar angle
where
From no-slip condition follows
Finally, integrating by parts, we obtain the Robin boundary condition for the vorticity:
Then the solution of the boundary-value problem can be expressed via Weber's integral above.
Remark
Formula for vorticity can give another explanation of the Stokes' Paradox. The functions belong to the kernel of and generate the stationary solutions of the vorticity equation with Robin-type boundary condition. From the arguments above any Stokes' vorticity flow with no-slip boundary condition must be orthogonal to the obtained stationary solutions. That is only possible for .