In algebraic topology, the path space fibration over a pointed space ( X , ∗ ) {\displaystyle (X,*)} [1] is a fibration of the form[2]
where
The free path space of X, that is, Map ( I , X ) = X I {\displaystyle \operatorname {Map} (I,X)=X^{I}} , consists of all maps from I to X that do not necessarily begin at a base point, and the fibration X I → X {\displaystyle X^{I}\to X} given by, say, χ ↦ χ ( 1 ) {\displaystyle \chi \mapsto \chi (1)} , is called the free path space fibration.
The path space fibration can be understood to be dual to the mapping cone.[clarification needed] The fiber of the based fibration is called the mapping fiber or, equivalently, the homotopy fiber.
If f : X → Y {\displaystyle f\colon X\to Y} is any map, then the mapping path space P f {\displaystyle P_{f}} of f {\displaystyle f} is the pullback of the fibration Y I → Y , χ ↦ χ ( 1 ) {\displaystyle Y^{I}\to Y,\,\chi \mapsto \chi (1)} along f {\displaystyle f} . (A mapping path space satisfies the universal property that is dual to that of a mapping cylinder, which is a push-out. Because of this, a mapping path space is also called a mapping cocylinder.[3])
Since a fibration pulls back to a fibration, if Y is based, one has the fibration
where p ( x , χ ) = χ ( 0 ) {\displaystyle p(x,\chi )=\chi (0)} and F f {\displaystyle F_{f}} is the homotopy fiber, the pullback of the fibration P Y ⟶ χ ↦ χ ( 1 ) Y {\displaystyle PY{\overset {\chi \mapsto \chi (1)}{\longrightarrow }}Y} along f {\displaystyle f} .
Note also f {\displaystyle f} is the composition
where the first map ϕ {\displaystyle \phi } sends x to ( x , c f ( x ) ) {\displaystyle (x,c_{f(x)})} ; here c f ( x ) {\displaystyle c_{f(x)}} denotes the constant path with value f ( x ) {\displaystyle f(x)} . Clearly, ϕ {\displaystyle \phi } is a homotopy equivalence; thus, the above decomposition says that any map is a fibration up to homotopy equivalence.
If f {\displaystyle f} is a fibration to begin with, then the map ϕ : X → P f {\displaystyle \phi \colon X\to P_{f}} is a fiber-homotopy equivalence and, consequently,[4] the fibers of f {\displaystyle f} over the path-component of the base point are homotopy equivalent to the homotopy fiber F f {\displaystyle F_{f}} of f {\displaystyle f} .
By definition, a path in a space X is a map from the unit interval I to X. Again by definition, the product of two paths α , β {\displaystyle \alpha ,\beta } such that α ( 1 ) = β ( 0 ) {\displaystyle \alpha (1)=\beta (0)} is the path β ⋅ α : I → X {\displaystyle \beta \cdot \alpha \colon I\to X} given by:
This product, in general, fails to be associative on the nose: ( γ ⋅ β ) ⋅ α ≠ γ ⋅ ( β ⋅ α ) {\displaystyle (\gamma \cdot \beta )\cdot \alpha \neq \gamma \cdot (\beta \cdot \alpha )} , as seen directly. One solution to this failure is to pass to homotopy classes: one has [ ( γ ⋅ β ) ⋅ α ] = [ γ ⋅ ( β ⋅ α ) ] {\displaystyle [(\gamma \cdot \beta )\cdot \alpha ]=[\gamma \cdot (\beta \cdot \alpha )]} . Another solution is to work with paths of arbitrary lengths, leading to the notions of Moore's path space and Moore's path space fibration, described below.[5] (A more sophisticated solution is to rethink composition: work with an arbitrary family of compositions; see the introduction of Lurie's paper,[6] leading to the notion of an operad.)
Given a based space ( X , ∗ ) {\displaystyle (X,*)} , we let
An element f of this set has a unique extension f ~ {\displaystyle {\widetilde {f}}} to the interval [ 0 , ∞ ) {\displaystyle [0,\infty )} such that f ~ ( t ) = f ( r ) , t ≥ r {\displaystyle {\widetilde {f}}(t)=f(r),\,t\geq r} . Thus, the set can be identified as a subspace of Map ( [ 0 , ∞ ) , X ) {\displaystyle \operatorname {Map} ([0,\infty ),X)} . The resulting space is called the Moore path space of X, after John Coleman Moore, who introduced the concept. Then, just as before, there is a fibration, Moore's path space fibration:
where p sends each f : [ 0 , r ] → X {\displaystyle f:[0,r]\to X} to f ( r ) {\displaystyle f(r)} and Ω ′ X = p − 1 ( ∗ ) {\displaystyle \Omega 'X=p^{-1}(*)} is the fiber. It turns out that Ω X {\displaystyle \Omega X} and Ω ′ X {\displaystyle \Omega 'X} are homotopy equivalent.
Now, we define the product map
by: for f : [ 0 , r ] → X {\displaystyle f\colon [0,r]\to X} and g : [ 0 , s ] → X {\displaystyle g\colon [0,s]\to X} ,
This product is manifestly associative. In particular, with μ restricted to Ω'X × Ω'X, we have that Ω'X is a topological monoid (in the category of all spaces). Moreover, this monoid Ω'X acts on P'X through the original μ. In fact, p : P ′ X → X {\displaystyle p:P'X\to X} is an Ω'X-fibration.[7]
Lemma—Let p: D → B, q: E → B be fibrations over an unbased space B, f: D → E a map over B. If B is path-connected, then the following are equivalent:
We apply the lemma with B = I , D = I × G , E = I × X P , f ( t , g ) = ( t , α ( t ) g ) {\displaystyle B=I,D=I\times G,E=I\times _{X}P,f(t,g)=(t,\alpha (t)g)} where α is a path in P and I → X is t → the end-point of α(t). Since p − 1 ( p ( γ ) ) = G {\displaystyle p^{-1}(p(\gamma ))=G} if γ is the constant path, the claim follows from the lemma. (In a nutshell, the lemma follows from the long exact homotopy sequence and the five lemma.)