Buromskiy Island is a small island lying 0.6 km (0.37 mi) south of Haswell Island in the Haswell Islands of Antarctica. About 200 m long and 100 m wide,[1] it was discovered and mapped by the Australasian Antarctic Expedition under Douglas Mawson, 1911–14. It was photographed by the Soviet expedition of 1958 and named for N.I. Buromskiy, expedition hydrographer who lost his life in the Antarctic in 1957.[2] It lies 2.7 km north of Mabus Point, the site of Russia's Mirny Station.