1995 Romanian Open – Doubles
1995 tennis event results
Wayne Arthurs and Simon Youl were the defending champions, but Youl retired from professional tennis at the end of the 1994 season.[1] Arthurs teamed up with Jordi Arrese and lost in the first round to Tom Kempers and Menno Oosting.
Mark Keil and Jeff Tarango won the title by defeating Cyril Suk and Daniel Vacek 6–4, 7–6 in the final.[2][3]
Seeds
Draw
Key
Draw
Qualifying
Qualifying seeds
Qualifiers
Jérôme Golmard / Fabrice Santoro
Qualifying draw
References
External links
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Grand Slam events | |
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ATP Championship Series, Single Week | |
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ATP Championship Series |
- Memphis (S, D)
- Milan (S, D)
- Philadelphia (S, D)
- Stuttgart Indoor (S, D)
- Barcelona (S, D)
- Tokyo Outdoor (S, D)
- Stuttgart Outdoor (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Tokyo Indoor (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Jakarta (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Dubai (S, D)
- Marseille (S, D)
- San Jose (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Mexico City (S, D)
- Copenhagen (S, D)
- St. Petersburg (S, D)
- Casablanca (S, D)
- Estoril (S, D)
- Johannesburg (S, D)
- Hong Kong (S, D)
- Nice (S, D)
- Bermuda (S, D)
- Seoul (S, D)
- Munich (S, D)
- Atlanta (S, D)
- Pinehurst (S, D)
- Coral Springs (S, D)
- Bologna (S, D)
- Rosmalen (S, D)
- Oporto (S, D)
- London/Queen's Club (S, D)
- St. Pölten (S, D)
- Halle (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Amsterdam (S, D)
- Kitzbühel (S, D)
- Prague (S, D)
- Los Angeles (S, D)
- San Marino (S, D)
- Long Island (S, D)
- Umag (S, D)
- Bucharest (S, D)
- Bogotá (S, D)
- Bordeaux (S, D)
- Palermo (S, D)
- Basel (S, D)
- Kuala Lumpur (S, D)
- Toulouse (S, D)
- Valencia (S, D)
- Tel Aviv (S, D)
- Ostrava (S, D)
- Lyon (S, D)
- Vienna (S, D)
- Beijing (S, D)
- Santiago (S, D)
- Montevideo (S, D)
- Buenos Aires (S, D)
- Stockholm (S, D)
- Moscow (S, D)
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Team events | |
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