1928 World Table Tennis Championships – Men's doubles

1928 Men's doubles
Location	Stockholm

Main article: 1928 World Table Tennis Championships

The 1928 World Table Tennis Championships men's doubles was the second edition of the men's doubles championship.^[1][2] Alfred Liebster and Robert Thum defeated Charles Bull and Fred Perry in the final by three sets to nil.^[3]

Results

^[2]

	Round of 16									Quarterfinals									Semifinals									Final
		Frank Wilde Charles Allwright	21	21	21
		S.R.G. Suppiah H.N. Bhorucha	17	13	15						Wilde Allwright	17	17	14
		Zoltán Mechlovits Roland Jacobi	21	21	21						Mechlovits Jacobi	21	21	21
		Cyril Mossford Solly Stone	16	6	16															Mechlovits Jacobi	14	18	12
		Folke Johansson Harald Feldin	9	21	6	8														Bull Perry	21	21	21
		Charles Bull Fred Perry	22	15	21	21					Bull Perry	21	21	13	15	21
		Antonín Maleček Erwin Fleischmann	21	16	16	17					Flussmann Pillinger	12	12	21	21	17
		Paul Flussmann Munio Pillinger	16	21	21	21																							Bull Perry	10	13	16
		Heribert Haensch Daniel Pecsi	8	12	21	21	22																						Liebster Thum	21	21	21
		Valter Kolmodin Hille Nilsson	21	21	18	15	20				Haensch Pecsi	14	13	21	11
		Laszlo Bellak Sándor Glancz	21	21	20	21					Bellak Glancz	21	21	18	21
		Harry Antonsson Ragnar Hallsten	11	11	22	12														Bellak Glancz	12	21	21	10	10+
		Alfred Liebster Robert Thum	19	21	22	21														Liebster Thum	21	9	14	21	18+
		Bernard Hookins Adrian Haydon	21	13	20	12					Liebster Thum	21	21	22
		D Baumgarten Herbert Caro	12	16	19						Coles Penny	16	10	20
		Trevor Coles Hedley Penny	21	21	21

+ retired

See also

List of World Table Tennis Championships medalists

References

1. "List of Winners". All About Tennis.
2. "1928 results" (PDF). International Table Tennis Federation. Archived from the original (PDF) on 2012-04-12.
3. Montague, Trevor (2004). A-Z of Sport, pages 699-700. The Bath Press. ISBN 0-316-72645-1.