Men kèk ekspresyon sekans nonm premye selon modèl boul wouj ak boul ble
P ( ( 1 − − --> [ [ ( n ! ) 2 n 3 ] ( n ! ) 2 n 3 ] ) × × --> ( ∑ ∑ --> m = 1 n ( 1 − − --> [ [ ( m ! ) 2 m 3 ] ( m ! ) 2 m 3 ] ) − − --> i ) + i ) = ( P i − − --> n ) × × --> [ [ ( n ! ) 2 n 3 ] ( n ! ) 2 n 3 ] + n {\displaystyle P_{\left(\left(1-\left[{\frac {\left[{\frac {\left(n!\right)^{2}}{n^{3}}}\right]}{\frac {\left(n!\right)^{2}}{n^{3}}}}\right]\right)\times \left(\sum _{m=1}^{n}{\left(1-\left[{\frac {\left[{\frac {\left(m!\right)^{2}}{m^{3}}}\right]}{\frac {\left(m!\right)^{2}}{m^{3}}}}\right]\right)}-i\right)+i\right)}=\left(P_{i}-n\right)\times \left[{\frac {\left[{\frac {\left(n!\right)^{2}}{n^{3}}}\right]}{\frac {\left(n!\right)^{2}}{n^{3}}}}\right]+n}
Strategi Solo vs Squad di Free Fire: Cara Menang Mudah!
![{\displaystyle P_{\left(\left(1-\left[{\frac {\left[{\frac {\left(n!\right)^{2}}{n^{3}}}\right]}{\frac {\left(n!\right)^{2}}{n^{3}}}}\right]\right)\times \left(\sum _{m=1}^{n}{\left(1-\left[{\frac {\left[{\frac {\left(m!\right)^{2}}{m^{3}}}\right]}{\frac {\left(m!\right)^{2}}{m^{3}}}}\right]\right)}-i\right)+i\right)}=\left(P_{i}-n\right)\times \left[{\frac {\left[{\frac {\left(n!\right)^{2}}{n^{3}}}\right]}{\frac {\left(n!\right)^{2}}{n^{3}}}}\right]+n}](https://wikimedia.org/api/rest_v1/media/math/render/svg/e44cd9b5e26eeef65d0b29e51e30b5700f58399f)
