There is nothing dubious about this unit; it is simply the reciprocal of spectral efficiency. Spectral efficiency is measured (typically) in bit/s/Hz, i.e. bit
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There is nothing dubious about this unit; it is simply the reciprocal of spectral efficiency. Spectral efficiency is measured (typically) in bit/s/Hz, i.e. bit/s per Hz. Crudely put, it is the ratio of the bit-rate vs. the spectral bandwidth used by the coding/modulation scheme. The higher this figure, the better, as it means that you're getting a higher information-rate for the same bandwidth.
The reciprocal of spectral efficiency is in units of Hz per bit/s; clearly the lower this figure is, the better. It describes, crudely, the amount of bandwidth required to transmit a given information rate.
Hz per bit, as was proposed as an alternative, is meaningless (in this context, at least). As a unit, it would imply that the bandwidth is related to the total number of bits transmitted.
This is basic comms theory and maths; so consequently, I've removed the dubious tags.
If you're still not happy, then we can re-write that section to talk about spectral efficiency rather than its reciprocal, because I admit that's not a commonly-used dimension. Oli Filth 01:46, 21 April 2007 (UTC)
It's useful in editing to remember that Manchester code is abstract from the means used to encode and decode it. It is often generated and decoded by software, so we should avoid suggesting (for example) that the decoder is "hardware" (or even that it's necessarily part of an electronic system). Mike Shepherd 11:36, 12 July 2007 (UTC)
Regarding the recent edit with the comment "by definition, a Fourier component is constant", we should distinguish between the "constant" results (the Fourier coefficients) of analysing a given segment of signal and the (typically different) results from analysis of another segment. A communication system exists precisely because these are different. It is in this sense that we might speak of the Fourier components changing in time. Thus (colloquially), we say "the DC component is constant" when we might say (more formally) that "the DC component is the same for any long segment of the signal". But let's remember that there's little point to an article which would satisfy a pure mathematician but which almost no-one else understands.Mike Shepherd 08:16, 25 August 2007 (UTC)
I'm easy with either version. I think I was being pedantic when I said that radio does not "usually" convey a DC component. Radio is a good example, but probably we should remove the word "usually". To me, the change from "which" to "that" makes the style colloquial (perhaps because I'm more familiar with British English), so I would never use the second form myself in a formal document. But I think either is OK, particularly if it's OK in American English.Mike Shepherd 14:33, 26 August 2007 (UTC)
Does anybody know where the name "Manchester Code" comes from? I have heard several explanantions but none of them did convince me. —The preceding unsigned comment was added by 87.165.10.155 (talk) 20:29, 21 February 2007 (UTC).
Firstly bandwidth is used incorrectly - the bandwidth of a Manchester coded signal is identical to the equivalent baseband signal. The frequency range on a baseband signal goes from DC to the baud rate. The maximum frequency on a Manchester coded line is twice the baud rate (which has implications for cabling, drive circuitry and attenuation), but the minimum frequency is the baud rate itself. The bandwidth is identical - equal to the baud rate in both situations.
Similarly "asynchronous communications" does not relate exclusively to carrier-less transmission standards - other standards may be used such as FSK. For example a 120 baud modem has a bandwidth of 1200 baud or 10 Hz/bit-second since the minimum frequency is 1200 Hz and the maximum 2400 Hz. It is still asynchronous in nature. Crispmuncher (talk) 19:40, 5 May 2010 (UTC)
I find this to have some similarities with the inversion lists' property of not handling the data, but the transition of the data bits. — Preceding unsigned comment added by 109.50.70.79 (talk) 23:19, 23 February 2012 (UTC)
The statement "... the encoding of each data bit has at least one transition and occupies the same time. It therefore has no DC component..." (an edit by 203.206.162.148 at 05:37, 2 February 2010) is false. Zero DC component requires more than these constraints. An obvious counterexample is a signal which is high for a short time, then low for the rest of the information bit time, this pattern repeated.Mike Shepherd (talk)
I have been using Manchester encoding since the mid 70's (1970's, not 1870's as some people in my office claim). There is one piece of information that I did not see anywhere in the article.
Since the Manchester code requires a transition in the middle of a bit, the code can be "broken" by removing this transition for one bit time. This places a data "Mark" in the bit stream. This mark can be either Low or High. A series of marks and bits is used as a header to identify data type and specify the start of the bit stream that follows.
In the day, we referred to this as "Bi-Phase Mark encoding", referring to the use of the mark in the Manchester code. Today, Manchester encoding is still used to transfer data. I currently use it for RFID cards. Hankpollinger (talk) 15:20, 4 June 2015 (UTC)
Manchester code is commonly refered to as Bi-phase-level or split phase in telemetry documentation including the Range Commanders Council document IRIG 106. I belive it would be constructive to include these as my search from bi-phase-level did not produce any results. --138.64.8.53 14:09, 30 January 2007 (UTC)Thad Sterling
Several articles that I read (perhaps originating from the same source) use bi-phase code and Manchester code as two equivalent terms for the same encoding. The description of "Biphase Mark Coding" here on Wikipedia (http://en.wikipedia.org/wiki/Biphase_Mark_Code) seems to confirm this. A link "see also ..." on this page might be useful (or an explanation where the difference lies).
Thiadmer Riemersma
I think the Manchester graph is wrong. The correct bits or drawing should be opposite depending on how you look at it. In Manchester Encoding, a 1-bit transits from negative to positive and vice versa for 0-bit.
SA DIP 25 Swl
I think it's important to note here somewhere that the bi-phase mark (and bi-phase space) are commonly referred to in some industries as FM1 and FM0, respectively. It's an important distinction as FM1 or FM0 (bi-phase mark or space) are easily decoded without reference to (absolute) phase at all. This simplicity exists since a transition occurs at the beginning of each bit period. This stands in contrast to Manchester encoded data where the (absolute) change of phase direction must be noted. FM0 and FM1 as common terms probably came about since they don't imply phase sensitity.
Gene Gajewski 11-Mar-2006 71.32.73.216 04:08, 12 March 2006 (UTC)
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