Module:Sandbox/Ineditable/Twitter

.mw-parser-output .documentation,.mw-parser-output .documentation-metadata{border:1px solid var(--border-color-base,#a2a9b1);background-color:#ecfcf4;color:inhe

Module:Sandbox/Ineditable/Twitter
local p = {}
 
function p.createLink( frame )
	local id = trim(frame.args.id or frame.args[1]) -- if not present should print an error. User friendly errors ¿?
	local name = trim(frame.args.name or frame.args[2] or "")
	local external = trim(frame.args.external or frame.args[3] or "")
	local newLine = trim(frame.args.newline or frame.args[4] or "")
	
	local patternUserRepresentation = '@' 
	
	-- remove @ from the beginning of the ID (if any)
	if id.sub(id, 1, string.len(patternUserRepresentation)) == patternUserRepresentation then id = id.sub(id, 2, string.len(id)) end
	
	-- repmove @ from the beginning of the user (if any)
	if name ~= '' and id.sub(name, 1, string.len(patternUserRepresentation)) == patternUserRepresentation then name = name.sub(name, 2, string.len(name)) end
			
	-- if the user is empty, use the ID, else use the name with a @
	if name == '' then name = '@'..id else name = '@'..name end
	
	-- write to output 
	local output = '[https://twitter.com/'.. id ..' '.. name ..']'
	
	if external == 'true' or external == '1' then output = output .. ' en [[Twitter]]' end 
	
	if newLine == 'true' or newLine == '1' then output = '* '.. output end 

    return output
end

function trim(s)
  return s:match'^%s*(.*%S)' or ''
end
 
return p

Content Disclaimer

Informasi ini disarikan dari Wikipedia dan disajikan kembali untuk tujuan edukasi. Konten tersedia di bawah lisensi CC BY-SA 3.0. Kami tidak bertanggung jawab atas ketidakakuratan data yang bersumber dari kontribusi publik tersebut.

  1. The information displayed on this website is sourced in part or in whole from Wikipedia and has been adapted for the purpose of restating it. We strive to provide accurate and relevant information, however:
  2. There is no guarantee of absolute accuracy. Wikipedia is an open, collaborative project that can be edited by anyone, so information is subject to change.
  3. It is not intended to constitute professional advice. The content displayed is for informational and educational purposes only. For important decisions (e.g., medical, legal, or financial), please consult a professional.
  4. Content copyright. Wikipedia is licensed under the Creative Commons Attribution-ShareAlike License (CC BY-SA). This means that content may be reused with appropriate attribution and shared under a similar license.
  5. Responsible use. Any risk arising from the use of information from this website is entirely the responsibility of the user.