The Battle of Surkonty took place on 21 August 1944. It is regarded as the first clash between the Polish Home Army and regular forces of the Red Army, supported by the NKVD.
The battle occurred in forests near the village of Surkonty, 20 kilometres (12 mi) northeast of Grodno, in the territory of Belarus, and resulted in a Polish defeat. The Soviets lost 132 men KIA, while Polish losses were 35 KIA (including local commandant, Colonel Maciej “Kotwicz” Kalenkiewicz) and 1 WIA.
Battle
In late June 1944, the unit of Kotwicz left the area of Grodno, and headed eastwards, to join Home Army forces from Stolpce in order to fight together in Operation Ostra Brama. On 13 July, the Home Army of the Vilnius Region, together with the Red Army, freed the city from the German invaders. Soon afterwards, the NKVD began arresting Polish soldiers, and as a result of this action, the local headquarters of the Home Army ordered all men to withdraw to the countryside.
On 18 July, at the edge of Rūdninkai forest, some 6,000 Home Army soldiers concentrated, together with 12,000 civilian refugees. They were soon spotted by Soviet aircraft, so it was decided that the soldiers should be divided into smaller groups, and march towards Białystok. The unit of Maciej Kalenkowicz remained in the forest for a while, but under Soviet pressure, it had to retreat southwest.
On 21 August, the Poles were attacked by the 3rd Battalion of the 32nd Motorized Regiment of the NKVD. The battle lasted five hours: Colonel Kalenkowicz was killed, together with 32 others, twenty of whom were bayoneted to death.[1]
