1996 Romanian Open

1996 Romanian Open
Date9–15 September
Edition4th
CategoryWorld Series
Draw32S / 16D
Prize money$475,000
SurfaceClay
LocationBucharest, Romania
VenueArenele BNR
Champions
Singles
Spain Alberto Berasategui[1]
Doubles
Sweden David Ekerot / United States Jeff Tarango[2]
← 1995 · Romanian Open · 1997 →

The 1996 Romanian Open was a men's tennis tournament played on outdoor clay courts at the Arenele BNR in Bucharest, Romania that was part of the World Series of the 1996 ATP Tour. It was the fourth edition of the tournament and was held from 9 September until 15 September 1996. Fourth-seeded Alberto Berasategui won the singles title.[3]

Finals

Singles

Main article: 1996 Romanian Open – Singles

Spain Alberto Berasategui defeated Spain Carlos Moyá 6–1, 7–6(7–5)

  • It was Berasategui's third title of the year and the 12th of his career.

Doubles

Main article: 1996 Romanian Open – Doubles

Sweden David Ekerot / United States Jeff Tarango defeated South Africa David Adams / Netherlands Menno Oosting 7–6, 7–6

  • It was Ekerot's second title of the year and of his career. It was Tarango's second title of the year and fifth of his career.

References

  1. ^ "1996 Bucharest – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "1996 Bucharest – Doubles draw". Association of Tennis Professionals (ATP).
  3. ^ John Barrett, ed. (1997). International Tennis Federation World of Tennis 1997. London: CollinsWillow. pp. 131, 151. ISBN 9780002187145.