1988 Belgian Open – Singles
1988 tennis event results
Kathleen Horvath was the defending champion but lost in the first round to Silvia La Fratta.
Arantxa Sánchez won in the final 6–0, 7–5 against Raffaella Reggi.
Seeds
A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.
Draw
Key
References
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Grand Slam events | |
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Category 5 tournaments | |
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Category 4 tournaments |
- Dallas (S, D)
- Oakland (S, D)
- Houston (S, D)
- Tokyo Indoor (S, D)
- Eastbourne (S, D)
- Cincinnati (S, D)
- New Orleans (S, D)
- Filderstadt (S, D)
- Brighton (S, D)
- Chicago (S, D)
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Category 3 tournaments | |
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Category 2 tournaments |
- Brisbane (S, D)
- Oklahoma City (S, D)
- Kansas (S, D)
- Tokyo Outdoor (S, D)
- Geneva (S, D)
- Strasbourg (S, D)
- Birmingham (S, D)
- Nice (S, D)
- Aix-en-Provence (S, D)
- San Diego (S, D)
- Sofia (S, D)
- Phoenix (S, D)
- Brentwood (S, D)
- Indianapolis (S, D)
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Category 1 tournaments |
- Buenos Aires (S, D)
- Guarujá (S, D)
- Auckland (S, D
- Wellington (S, D)
- Singapore (S, D)
- Taiwan (S, D)
- Taranto (S, D)
- Barcelona (S, D)
- Båstad (S, D)
- Brussels (S, D)
- OTB Open (S, D)
- Aptos (S, D)
- Athens (S, D)
- Paris (S, D)
- San Juan (S, D)
- Guarujá II (S, D)
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Team events | |
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