1888 United States presidential election in Delaware

Main article: 1888 United States presidential election

1888 United States presidential election in Delaware

November 6, 1888

Nominee Grover Cleveland Benjamin Harrison Party Democratic Republican Home state New York Indiana Running mate Allen G. Thurman Levi P. Morton Electoral vote 3 0 Popular vote 16,414 12,950 Percentage 55.15% 43.51%

County Results Cleveland   50-60% Harrison   40-50%

President before election Grover Cleveland Democratic Elected President Benjamin Harrison Republican

The 1888 United States presidential election in Delaware took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a margin of 11.64%.

This was the last time until 2000 that a Republican was elected president without winning Delaware.

Results

1888 United States presidential election in Delaware[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Grover Cleveland of New York (incumbent)	Allen Granberry Thurman of Ohio	16,414	55.15%	3	100.00%
	Republican	Benjamin Harrison of Indiana	Levi Parsons Morton of New York	12,950	43.51%	0	0.00%
	Prohibition	Clinton Bowen Fisk of New Jersey	John Anderson Brooks of Missouri	399	1.34%	0	0.00%
	N/A	Others	Others	1	<0.01%	0	0.00%
Total				29,764	100.00%	3	100.00%

See also

• United States presidential elections in Delaware

Notes

References

1. "1888 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved December 23, 2013.