1845 Mississippi gubernatorial election

1845 Mississippi gubernatorial election

November 3, 1845

Nominee Albert G. Brown Thomas B. Coopwood Party Democratic Whig Popular vote 28,310 12,852 Percentage 66.1% 30.0%

County results Brown:      50–60%      60–70%      70–80%      80–90%      90–100% Coopwood:      50–60%      60–70%

Governor before election Albert G. Brown Democratic Elected Governor Albert G. Brown Democratic

The 1845 Mississippi gubernatorial election was held on November 3, 1845, to elect the governor of Mississippi. Albert G. Brown, a Democrat won against Whig Thomas Coopwood and candidate Issac N. Davis.^[1][2]

Results

Mississippi gubernatorial election, 1845^[1]^[3]^[4]

Party		Candidate	Votes	%
	Democratic	Albert G. Brown	28,310	66.1%
	Whig	Thomas B. Coopwood	12,852	30.0%
		Issac N. Davis	1,683	3.9%
Total votes			42,854	100.00
	Democratic hold

References

1. Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 168–169.
2. Rowland, Dunbar (1925). History of Mississippi, the Heart of the South. Vol. 1. S. J. Clarke publishing Company.
3. Dublin, Michael J. (2011). United States Gubernatorial Elections, 1776-1860 : The Official Results by State and County. McFarland & Company, Incorporated Publishers. p. 132. ISBN 9780786453245.
4. "The Results for Governor" (fee required). The Mississippi Trader and Natchez Gazette. January 17, 1846. p. 2.