1996 United States presidential election in Hawaii
1996 United States presidential election in Hawaii|
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County Results
Clinton 50–60% 60–70% 70–80%
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The 1996 United States presidential election in Hawaii took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.
Hawaii was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 56.93% to 31.64% by a margin of 25.29%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 7.6% of the popular vote.[1]
Results
By county
County
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Bill Clinton Democratic
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Bob Dole Republican
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Various candidates Other parties
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Margin
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Total votes cast
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#
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%
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#
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%
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#
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%
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#
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%
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Hawaii
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27,262
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55.66%
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13,516
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27.60%
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8,199
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16.74%
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13,746
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28.06%
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48,977
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Honolulu
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143,793
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56.33%
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85,779
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33.61%
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25,684
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10.06%
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58,014
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22.72%
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255,256
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Kalawao
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46
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73.02%
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13
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20.63%
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4
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6.35%
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33
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52.39%
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63
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Kauai
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13,357
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63.54%
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5,325
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25.33%
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2,338
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11.13%
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8,032
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38.21%
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21,020
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Maui
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20,600
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59.08%
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9,323
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26.74%
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4,944
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14.18%
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11,277
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32.34%
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34,867
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Totals |
205,012 |
56.93% |
113,943 |
30.04% |
41,165 |
11.43% |
91,069 |
25.29% |
360,120
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References
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