1994 Benson and Hedges Open – Doubles
1994 tennis event results
Grant Connell and Patrick Galbraith were the defending champions, but lost in the final this year.
Patrick McEnroe and Jared Palmer won the title, defeating Connell and Galbraith 6–2, 4–6, 6–4 in the final.[1]
Seeds
Draw
Key
Draw
References
External links
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Grand Slam events | |
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ATP Championship Series, Single Week | |
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ATP Championship Series |
- Milan (S, D)
- Memphis (S, D)
- Philadelphia (S, D)
- Stuttgart Indoor (S, D)
- Barcelona (S, D)
- Tokyo Outdoor (S, D)
- Stuttgart Outdoor (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Sydney Indoor (S, D)
- Tokyo Indoor (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Oahu (S, D)
- Jakarta (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Dubai (S, D)
- Marseille (S, D)
- San Jose (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Mexico City (S, D)
- Copenhagen (S, D)
- Zaragoza (S, D)
- Casablanca (S, D)
- Osaka (S, D)
- Estoril (S, D)
- Sun City (S, D)
- Hong Kong (S, D)
- Nice (S, D)
- Birmingham (S, D)
- Seoul (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Madrid (S, D)
- Pinehurst (S, D)
- Coral Springs (S, D)
- Bologna (S, D)
- Florence (S, D)
- London/Queen's Club (S, D)
- Rosmalen (S, D)
- Halle (S, D)
- St. Pölten (S, D)
- Manchester (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Hilversum (S, D)
- Kitzbühel (S, D)
- Prague (S, D)
- Los Angeles (S, D)
- San Marino (S, D)
- Long Island (S, D)
- Schenectady (S, D)
- Umag (S, D)
- Bucharest (S, D)
- Bordeaux (S, D)
- Bogotá (S, D)
- Palermo (S, D)
- Kuala Lumpur (S, D)
- Basel (S, D)
- Toulouse (S, D)
- Athens (S, D)
- Ostrava (S, D)
- Tel Aviv (S, D)
- Vienna (S, D)
- Lyon (S, D)
- Beijing (S, D)
- Santiago (S, D)
- Montevideo (S, D)
- Buenos Aires (S, D)
- Moscow (S, D)
- Antwerp (S, D)
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Team events | |
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