1966 Iowa gubernatorial election

1966 Iowa gubernatorial election

November 8, 1966

Nominee Harold Hughes William G. Murray Party Democratic Republican Popular vote 494,259 394,518 Percentage 55.34% 44.17%

County results Hughes:      50–60%      60–70%      70–80% Murray:      40–50%      50–60%      60–70%

Governor before election Harold Hughes Democratic Elected Governor Harold Hughes Democratic

The 1966 Iowa gubernatorial election was held on November 8, 1966. Incumbent Democrat Harold Hughes defeated Republican nominee William G. Murray with 55.34% of the vote.

Primary elections

Primary elections were held on September 6, 1966.^[1]

Democratic primary

Candidates

• Harold Hughes, incumbent Governor

Results

Democratic primary results^[1]

Party		Candidate	Votes	%
	Democratic	Harold Hughes (incumbent)	80,198	100.00
Total votes			80,198	100.00

Republican primary

Candidates

• William G. Murray, Iowa State University Professor of Economics
• Robert K. Beck, former State Representative

Results

Republican primary results^[1]

Party		Candidate	Votes	%
	Republican	William G. Murray	87,371	50.5
	Republican	Robert K. Beck	85,733	49.5
Total votes			173,109	100.00

General election

Candidates

Major party candidates

• Harold Hughes, Democratic
• William G. Murray, Republican

Other candidates

• David B. Quiner, Independent
• Charles Sloca, Independent

Results

1966 Iowa gubernatorial election^[2]

Party		Candidate	Votes	%	±%
	Democratic	Harold Hughes (incumbent)	494,259	55.34%
	Republican	William G. Murray	394,518	44.17%
	Independent	David B. Quiner	3,680	0.41%
	Independent	Charles Sloca	715	0.08%
Majority			99,741
Turnout			893,175
	Democratic hold		Swing

References

1. "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1966. Retrieved March 20, 2020.
2. "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1966. Retrieved March 20, 2020.