1928 U.S. National Championships – Women's singles

Women's singles
1928 U.S. National Championships
Champion	Helen Wills
Runner-up	Helen Jacobs[1]
Score	6–2, 6–1

First-seeded Helen Wills defeated Helen Jacobs 6–2, 6–1 in the final to win the women's singles tennis title at the 1928 U.S. National Championships. The event was held at the West Side Tennis Club, Forest Hills, New York City. It was Wills's fifth U.S. National singles title and her second in a row.^[1] Wills won the tournament without losing a set.^[2]

Seeds

The tournament assigned eight seeded players for the women's singles event. Helen Wills is the champion; others show in brackets the round in which they were eliminated.

1. Helen Wills (champion)
2. Molla Mallory (semifinals)
3. Helen Jacobs (finalist)
4. Edith Cross (semifinals)
5. Charlotte Hosmer Chapin (quarterfinals)
6. Marjorie Morrill (quarterfinals)
7. Penelope Anderson (quarterfinals)
8. May Sutton Bundy (third round)

Draw

Final eight

	Quarterfinals							Semifinals							Finals
	1	Helen Wills	6	6
	5	Charlotte Hosmer Chapin	2	4
								1	Helen Wills	6	6
								4	Edith Cross	0	1
		Hazel Hotchkiss Wightman	3	4
	4	Edith Cross	6	6
															1	Helen Wills	6	6
															3	Helen Jacobs	2	1
	3	Helen Jacobs	6	6
	5	Penelope Anderson	4	1
								3	Helen Jacobs	6	7
								2	Molla Mallory	2	5
	6	Marjorie Morrill	2	6	3
	2	Molla Mallory	6	3	6

References

1. Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 469. ISBN 978-0942257700.
2. "The Peerless Mrs. Helen Wills-Moody". Brooklyn Daily Times. 19 August 1931. Retrieved 30 September 2024.

Preceded by 1928 Wimbledon Championships – Women's singles

Grand Slam women's singles

Succeeded by 1929 Australian Championships – Women's singles