1896 United States presidential election in Rhode Island

Main article: 1896 United States presidential election

1896 United States presidential election in Rhode Island

November 3, 1896

Nominee William McKinley William Jennings Bryan Party Republican Democratic Home state Ohio Nebraska Running mate Garret Hobart Arthur Sewall Electoral vote 4 0 Popular vote 37,437 14,459 Percentage 68.33% 26.39%

County Results McKinley   60-70%   70-80%

President before election Grover Cleveland Democratic Elected President William McKinley Republican

The 1896 United States presidential election in Rhode Island took place on November 3, 1896, as part of the 1896 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won the state by a wide margin of 41.94%.

Bryan, running on a platform of free silver, appealed strongly to Western miners and farmers in the 1896 election, but had little appeal in Northeastern states like Rhode Island.

With 68.33% of the popular vote, Rhode Island would be McKinley's fourth strongest victory in terms of percentage in the popular vote after Vermont, neighboring Massachusetts and New Hampshire.^[1]

Bryan would lose Rhode Island to McKinley again four years later and would later lose the state again in 1908 to William Howard Taft.

Results

1896 United States presidential election in Rhode Island[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	William McKinley of Ohio	Garret Hobart of New Jersey	37,437	68.33%	4	100.00%
	Democratic	William Jennings Bryan of Nebraska	Arthur Sewall of Maine	14,459	26.39%	0	0.00%
	National Democratic	John McAuley Palmer of Illinois	Simon Bolivar Buckner of Kentucky	1,166	2.13%	0	0.00%
	Prohibition	Joshua Levering of Maryland	Hale Johnson of Illinois	1,160	2.12%	0	0.00%
	Socialist Labor	Charles Horatio Matchett of New York	Matthew Maguire of New Jersey	558	1.02%	0	0.00%
	N/A	Others	Others	5	0.01%	0	0.00%
Total				54,785	100.00%	4	100.00%

See also

• United States presidential elections in Rhode Island

References

1. "1896 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
2. "1896 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.